(a^14+bc)(a^14-bc)=

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Solution for (a^14+bc)(a^14-bc)= equation: 


Simplifying
(a14 + bc)(a14 + -1bc) = 0

Multiply (a14 + bc) * (a14 + -1bc)
(a14(a14 + -1bc) + bc(a14 + -1bc)) = 0
((a14 * a14 + -1bc * a14) + bc(a14 + -1bc)) = 0

Reorder the terms:
((-1a14bc + a28) + bc(a14 + -1bc)) = 0
((-1a14bc + a28) + bc(a14 + -1bc)) = 0
(-1a14bc + a28 + (a14 * bc + -1bc * bc)) = 0
(-1a14bc + a28 + (a14bc + -1b2c2)) = 0

Reorder the terms:
(-1a14bc + a14bc + a28 + -1b2c2) = 0

Combine like terms: -1a14bc + a14bc = 0
(0 + a28 + -1b2c2) = 0
(a28 + -1b2c2) = 0

Solving
a28 + -1b2c2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'b2c2' to each side of the equation.
a28 + -1b2c2 + b2c2 = 0 + b2c2

Combine like terms: -1b2c2 + b2c2 = 0
a28 + 0 = 0 + b2c2
a28 = 0 + b2c2
Remove the zero:
a28 = b2c2

Simplifying
a28 = b2c2

Combine like terms: b2c2 + -1b2c2 = 0
a28 + -1b2c2 = 0

Factor a difference between two squares.
(a14 + bc)(a14 + -1bc) = 0


Subproblem 1
Set the factor '(a14 + bc)' equal to zero and attempt to solve:

Simplifying
a14 + bc = 0

Solving
a14 + bc = 0

Move all terms containing a to the left, all other terms to the right.

Add '-1bc' to each side of the equation.
a14 + bc + -1bc = 0 + -1bc

Combine like terms: bc + -1bc = 0
a14 + 0 = 0 + -1bc
a14 = 0 + -1bc
Remove the zero:
a14 = -1bc

Simplifying
a14 = -1bc

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

Subproblem 2
Set the factor '(a14 + -1bc)' equal to zero and attempt to solve:

Simplifying
a14 + -1bc = 0

Solving
a14 + -1bc = 0

Move all terms containing a to the left, all other terms to the right.

Add 'bc' to each side of the equation.
a14 + -1bc + bc = 0 + bc

Combine like terms: -1bc + bc = 0
a14 + 0 = 0 + bc
a14 = 0 + bc
Remove the zero:
a14 = bc

Simplifying
a14 = bc

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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